w/w-4-2w/2w-5=w-2/2w^2-13w+20

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Solution for w/w-4-2w/2w-5=w-2/2w^2-13w+20 equation: 


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

w/w-(((2*w)/2)*w)-5-4 = w-((2/2)*w^2)-(13*w)+20 // - w-((2/2)*w^2)-(13*w)+20

(2/2)*w^2-(((2*w)/2)*w)-w+13*w+w/w-20-5-4 = 0

(2/2)*w^2-w^2-w+13*w+w/w-20-5-4 = 0

12*w-28 = 0 // + 28

12*w = 28 // : 12

w = 28/12

w = 7/3

w = 7/3

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